What is radiant energy?: photons. Any object above absolute zero will radiate photons. Photons are not heat. Photons are a form of EM radiation. A cold body will radiate photons.
Look up Plank's law on black body radiation. It's PHOTONS being radiated, NOT heat.
You guys always (warmers) go there when there is no "there" to go to because we are already here and have been since this phase of the conversation started.
In the first place, the earth is not a blackbody so the assumption that it acts as a black body in energy balance models of the earth is off the reservation from the very beginning. In the second place, this may surprise you, but EM radiation includes radio waves, microwaves, terahertz radiation,
infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays. A photon is merely the smallest possible unit of each of these forms of radiation. Each type describes a different wavelength.
IR radiation IS electromagnetic radiation. You haven't introduced a different type of radiation into the conversation, you have only begun to call IR electromagnetic radiation when, in reality, they are one in the same. Is this a deliberate strawman or an attempt to decieve, or were you really unaware that IR is, in fact, a wavelength of electromagnetic radiation?
Photon - The subatomic particle that carries the electromagnetic force
and is the quantum of electromagnetic radiation.
In case there is any question, quantum is defined as :
A discrete, indivisible manifestation of a physical property, such
as a force or angular momentum. Some quanta take the form of
elementary particles;
for example, the quantum of electromagnetic radiation
is the
photon, while the quanta of the
weak force are the W and Z
particles
I am going to go out on a limb here and assume that you are familiar with the Stefan-Boltzman law.
When we are discussing the emissivity of an object radiating into a cooler background, the law takes the form:
(watts per square meter)
if we rearrange the equation, we get:
This is clearly a subtraction of two EM fields. It is predicted by and in compliance with the vector subtraction of EM fields which are vectors. You subtract the smaller field from the larger and the resulting field will have a magnitude equal to P/A and be propagated in a direction away from the field of greater magnitude. Slice it, dice it, make julienne fries out of it if you like, but there is no transfer of energy from cool to warm precisely as the second law of thermodynamics predicts. If it were possible, then perpetual motion would be possible.
Radiated EM, no matter which wavelength of EM we are talking about are vector fields and as such, must be treated as vector fields. If you are familiar EM physics, then you must be familiar with the interference properties of EM fields. The physics of electromagnetism has been in daily use by folks ranging from physicists to electrical engineers for over a hundred years now. The topic is well documented via observable, repeatable experimentation unlike climate science which doesn't rely on observable repeatable experimentation but rather lives on the output of flawed models.
The fact that EM fields in opposition to each other can cause interference and even result in the complete cancellation of one, or the other is well known and documented and is a critical consideration in the design of each and every TV/Radio tower, microwave transmitter, satellite link, and optical / IR link in existence. All EM radiation is subject to interference, addition, subtraction, and cancellation.
I repeat, no energy transfer exists between the cooler atmosphere and the warmer surface of the earth as predicted by the second law of thermodynamics, the law of conservation of energy, and the Stefan-Boltzman law.
Suppose you are a cold body. You radiate some IR photons everywhere since you are a bit above absolute zero. If you deny this, then you are denying everything in thermodynamic understanding, black body radiation, emissivity, not to mention climate science which I suppose you already deny.
Yep, if I am a cold body I am radiating some electromagnetic radiation. (so long as my temperature is above absolute zero) And all those photons I am radiating constitue vectors radiating off in various directions. If I am radiating off into a background colder than myself, the EM radiation I am putting out just goes off in all directions.
Suppose I am a warm body nearby. Some of your photons will be directly aimed at me. Just what happens to those photons They don't deviate in flight. They don't disappear in flight. They do hit me at the speed of light. How can you argue against that.
Yep, some of my photons will be directed at you and at the same time, some of your photons will be directed at me. At every point where our photons are in opposition, we must subtract those vectors. Since you are warmer, we will subtract the magnitude of my EM vectors from the magnitude of your EM vectors and the resulting EM field will be the difference between my magnitude and your magnitude and the direction of propagation of the resulting EM field will be away from your warmer body. None of my photons will ever reach you although they will diminish the original magnitude of the EM field you are propagating.
Since I am a warmer body, I emit more and higher energy photons everywhere, including at you. My photons will outdo your photons and you will heat up by virtue of absorbing my photons. I will not heat up. Really. If you can't understand this and deny it, all that's left in this thread is your angry bitter vitriol.
You aren't using your brain lagboltz. Lets follow your thinking to its logical conclusion. If you were able to absorb any of my photons, you would then warm up by some small bit and as a result radiate more energy out which I would then
absorb and become warmer and thus radiate more energy out which you would then absorb and thus become warmer and in turn radiate out more energy which I would then absorb and become warmer and thus radiate more energy out which you would then.....
See where this is going? If you, as the warmer body could absorb energy from me, the colder body, we would get stuck in a postive feedback loop till both of us become infinitely hot. What you aren't getting in your final statement is that if you absorb any of my photons, even one, you will become warmer and then be radiating all of the energy you were radiating plus that photon(s) that you got from me. If you absorbed even one photon from me, by definition, you would have to warm up even if it was only by an infinitestimal amount at the beginning of the positive feedback loop.
Like it or not lagboltz, there is no transfer of energy from the cooler atmosphere to the warmer earth and therefore no greenhouse effect as claimed by climate science. There is an atmospheric thermal effect which is, in reality, much greater than the greenhouse effect, but it isn't dependent upon the compositon of the atmosphere. To understand why the earth is the temperature it is, you need not look much further than the ideal gas laws. A politically motivated greenhouse effect is not necessary.